Question
Question: In an NPN transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach ...
In an NPN transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector, the emitter current (iE) and base current (iB) are given by
A
iE = – 1 mA, iB = 9 mA
B
iE = 9 mA, iB = – 1 mA
C
iE = 1 mA, iB = 11 mA
D
iE = 11 mA, iB = 1 mA
Answer
iE = 11 mA, iB = 1 mA
Explanation
Solution
iC=10090×iE⇒ 10 = 0.9 × iE = 11mA
Also iE=iB+iC⇒iB=11−10=1mA.