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Question: In an NPN transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach ...

In an NPN transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector, the emitter current (iE) and base current (iB) are given by

A

iE = – 1 mA, iB = 9 mA

B

iE = 9 mA, iB = – 1 mA

C

iE = 1 mA, iB = 11 mA

D

iE = 11 mA, iB = 1 mA

Answer

iE = 11 mA, iB = 1 mA

Explanation

Solution

iC=90100×iEi_{C} = \frac{90}{100} \times i_{E}⇒ 10 = 0.9 × iE = 11mA

Also iE=iB+iCiB=1110=1mA.i_{E} = i_{B} + i_{C} \Rightarrow i_{B} = 11 - 10 = 1mA.