Question

In an n – p – n circuit transistor, the collector current is 10 mA. If 80% electron emitted reach the collector, then

• A. The emitter current will be $7.5mA$
• B. The emitter current will be $12.5mA$
• C. The base current will be $3.5mA$
• D. The base current will be $1.5mA$

Answer 1

Answer: (B)

The emitter current will be $12.5mA$

Answer 2

: here, $I_{C} = 80\% ofI_{E} = \frac{80}{100}I_{E}$

Or $I_{E} = \frac{I_{C}}{0.8} = \frac{10}{0.8} = 12.5mA$

$I_{B} = I_{E} - I_{C} = 12.5 - 10 = 2.5mA$