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Physics Question on Current Electricity

In an LCR series circuit, the source of emf is E=30sin(100t), R=120Ω, L=100mH, C=100μF.
(A) The numerical value of impedance
(B) The numerical value of resistance R
(C) The numerical value of capacitive reactance
(D) The numerical value of inductive reactance.
Arrange the values of quantities mentioned in (A, B, C, D) in increasing order.

A

(A), (B), (C), (D)

B

(A), (C), (B), (D)

C

(B), (A), (D), (C)

D

(D), (C), (B), (A)

Answer

(B), (A), (D), (C)

Explanation

Solution

 To solve this, we need to compute:\text{ To solve this, we need to compute:} \\\\
− The capacitive reactance XC=1ωC,- \text{ The capacitive reactance } X_C = \frac{1}{\omega C}, \\\\
− The inductive reactance XL=ωL,- \text{ The inductive reactance } X_L = \omega L, \\\\
− The impedance Z=R2+(XL−XC)2.- \text{ The impedance } Z = \sqrt{R^2 + (X_L - X_C)^2}. \\\\

Where ω=100 rad/s. After calculating each value, we can arrange them in increasing order.\text{Where } \omega = 100 \, \text{rad/s}. \text{ After calculating each value, we can arrange them in increasing order.}