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Question: In an LCR circuit the potential difference between the terminals of the inductance is \[60V\], betwe...

In an LCR circuit the potential difference between the terminals of the inductance is 60V60V, between the terminals of the capacitor is 30V30V and that between the terminals of resistance is 40V40V. The supply voltage will be:
A) 25V25V
B) 50V50V
C) 100V100V
D) 200V200V

Explanation

Solution

Inductance opposes the change in the current and serves to delay the decrease or increase of current in the circuit. This causes the circuit current to lag behind the applied voltage in an inductive circuit. Capacitance opposes the change in voltage and serves to delay the increase or decrease of voltage across the capacitor. This causes the voltage to lag behind the current in a capacitive circuit.

Complete step by step answer:
Consider a circuit containing an inductor, capacitor and resistor connected in series across an alternating source of voltage VV or emf ε\varepsilon .

Let the source supplies a sinusoidal voltage which is given by,
V=V0sinωtV = {V_0}\sin \omega t
Where, V0{V_0} is the peak value of voltage ω\omega is the angular frequency and tt is the time period.
Let q be the charge on the capacitor and II be the current in the circuit at any instant of time tt.
Let VR,VL,VC{V_R},{V_L},{V_C} represent the voltage across the resistor, inductor and capacitor respectively.
Then, voltage across resistor, VR=i0R{V_R} = {i_0}R
Voltage across inductor, VL=i0XL{V_L} = {i_0}{X_L}
Voltage across capacitor, VC=i0XC{V_C} = {i_0}{X_C}
Where, i0{i_0} is the peak value of current, XC{X_C} is capacitive reactance, XL{X_L} is the inductive reactance and RR is the resistance of the resistor.
Then net voltage or emf is given by,VV orε=(VR2+(VLVC)2)\varepsilon = \sqrt {\left( {{V_R}^2 + {{\left( {{V_L} - {V_C}} \right)}^2}} \right)} …………….(1)
Given, potential difference across inductor,VL=60V{V_L} = 60V
Potential difference across capacitor,VC=30V{V_C} = 30V
Potential difference across resistor,VR=40V{V_R} = 40V
Now substitute these values in equation (1), we get
ε=(402+(6030)2)\varepsilon = \sqrt {\left( {{{40}^2} + {{\left( {60 - 30} \right)}^2}} \right)}
ε=(1600+900)=50V\rightarrow \varepsilon = \sqrt {\left( {1600 + 900} \right)} = 50V
\therefore The supply voltage will be 50V

Thus, the correct option is (B).

Additional information:
The main difference between a direct current and an alternating current is;
A direct current always flows in one direction in the circuit. However, an alternating current flows periodically in an alternate direction in the circuit.
A direct current has a constant value whereas the value of alternating current varies from instant to instant.

Note: Opposition offered by an inductor for the flow of ac is called ‘inductive reactance’.
An alternating voltage is one whose magnitude changes with time and direction changes periodically.
Frequency of direct current is zero. That is direct current is independent of frequency.