Question
Question: In an \(LCR\) circuit, capacitance is changed from \(C\) to \(2C\). For the resonant frequency to re...
In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency to remain unchanged, the inductance should be changed from L to :
A. 4L
B. 2L
C. 2L
D. 4L
Solution
a LCR circuit is an electronic circuit which is a combination of capacitor, inductor and resistor which are either connected in series or in parallel. For the resonance condition inductive reactance becomes equal to capacitive reactance.
Formula used:
XL=XC
Where XL= inductive reactance and XC=capacitive reactance.
Complete step by step answer:
The resonance of a series LCR circuit occurs when the inductive and capacitive reactance are equal in magnitude but cancel each other because they are 180 degrees apart in phase. In resonance condition a circuit acts as a pure resistive circuit and has maximum current in it.
In LCR circuit, the impedance is given by:
Z2=R2+(XL−XC)2
where R is resistance, XL= inductive reactance and XC=capacitive reactance.
At Resonance in LCR circuit,
XL=XC
⇒ωL=ωC1
⇒ω2=LC1
⇒ω=LC1
In the resonance condition the frequency remains unchanged. Hence LC=constant. It means that even LC is constant. Hence we can write that :
L1C1=L2C2
Where L2 is inductance initially and L2 is final inductance.
We know that here C1=C and C2=2C let us now substitute these values, we get:
L1C=L22C
⇒L2=2CL1C
∴L2=2L1
Hence the correct answer is option B.
Note: depending on the values of the reactance the behavior of the circuit changes, like: If XL>XC the circuit is inductive in nature, if XL<XC, the circuit behaves like a capacitive circuit and if XL=XC. Also note that XL=ωL and not XL=ωL1 whereas XC=ωC1 and not XC=ωC.