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Question

Physics Question on Alternating current

In an LRL-R circuit, time constant is that time in which current grows from zero to the value where I0 I_{0} is steady state current.

A

0.63I0 0.63I_{0}

B

0.50I0 0.50I_{0}

C

0.37I0 0.37I_{0}

D

I0I_{0}

Answer

0.63I0 0.63I_{0}

Explanation

Solution

The equation for growth of current in LRL-R circuit is given by I=I0(1et/τ)I=I_{0}\left(1-e^{-t / \tau}\right) Here, τ(=LR)\tau\left(=\frac{L}{R}\right) is called time constant of the LRL-R circuit. At a time equal to one time constant iei e, at t=τt=\tau I=I0(1e1)I=I_{0}\left(1-e^{-1}\right) or I=I0(11e)I=I_{0}\left(1-\frac{1}{e}\right) or I=0.63I0I=0.63 I_{0}