Question

In an isothermal reversible expansion, if the volume of 96 gm of oxygen at 27°C is increased from 70 litres to 140 litres, then the work done by the gas will be

• A. $300R\log_{10}2$
• B. $81R\log_{e}2$
• C. $900R\log_{10}2$
• D. $2.3 \times 900R\log_{10}2$

Answer 1

Answer: (D)

$2.3 \times 900R\log_{10}2$

Answer 2

$W = \mu RT\log_{e}\frac{V_{2}}{V_{1}}$

$= \left( \frac{m}{M} \right)RT\log_{e}\frac{V_{2}}{V_{1}} = 2.3 \times \frac{m}{M}RT\log_{10}\frac{V_{2}}{V_{1}}$

$= 2.3 \times \frac{96}{32}R(273 + 27)\log_{10}\frac{140}{70} = 2.3 \times 900R\log_{10}2$