Question

In an isobaric process, the ratio of heat supplied to the system (dQ) and work done by the system (dW) for diatomic gas is

• A. 1 : 1
• B. 7 : 2
• C. 7 : 5
• D. 5 : 7

Answer 1

Answer: (B)

7 : 2

Answer 2

$dE = dW + dQ; - dW = dQ - dE\therefore\frac{dQ}{dW} = \frac{dQ}{dQ - dE}$

= $\frac{C_{p}}{\left( C_{p} - C_{v} \right)}$

= $\frac{7R}{2R}$ (cp = $\frac{7R}{2}$)