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Question

Physics Question on Wave optics

In an interference experiment, when a glass plate of refractive index 1.5 is introduced in the path of one of the beams; fringes are displaced by xx. When the glass plate is replaced by another transparent plate of same thickness, shift in the fringe is 32x. \frac{3}{2} x . Refractive index of 2nd2^{nd} transparent plate is

A

2.25

B

2

C

1.75

D

1.25

Answer

1.75

Explanation

Solution

Shift in fringe pattern due to introduction of glass plate in the path. of one of slits in Young's.double slit experiment is given by, Δy=D(μ1)td\Delta y = \frac{D(\mu - 1) t}{d}
Here, μ1=1.5,Δy1=x,\mu_{1} = 1.5 , \Delta y_{1} =x ,
Δy2=32x,t1=t2=t,μ2=?\Delta y_{2} = \frac{3}{2}x, t_{1} = t_{2} = t, \mu_{2} =?
Δy1Δy2=(μ11)t1(μ21)t2\frac{\Delta y_{1}}{\Delta y_{2}} = \frac{\left(\mu_{1} -1 \right)t_{1}}{\left(\mu _{2} -1\right)t_{2}}
or,x32x=(1.51)(μ21) \frac{x}{\frac{3}{2}x} = \frac{\left(1.5 -1\right)}{\left(\mu_{2} -1\right) }
or, μ21=32×0.5\mu_{2} -1 = \frac{3}{2} \times0.5
or, μ2=1+34=74=1.75\mu_{2} = 1+ \frac{3}{4} = \frac{7}{4} = 1.75