Question

In an ideal transformer, the voltage and the current in the primary are 200 V, 2A and that in the secondary are 2000 V, I A. The value of I is (A)

• A. 0.2
• B. 1
• C. 20
• D. 2

Answer 1

Answer: (A)

0.2

Answer 2

Using $\frac{V_p}{V_s} = \frac{I_p}{I_s}$ we get $\frac{200}{2000} = \frac{I}{2} \, i.e.$ I = 0.2 A.