Question

In an ideal transformer, the turns ratio is $N_p/N_s$ =1/2 .The ratio $V_S:V_P$ is equal to (the symbols carry their usual meaning):

• A. 1:2
• B. 1:1
• C. 2:1
• D. 1:4

Answer 1

Answer: (B)

1:1

Answer 2

In an ideal transformer, the voltage ratio is directly proportional to the turns ratio:

$\frac{V_s}{V_p} = \frac{N_s}{N_p}$

Given $\frac{N_p}{N_s} = \frac{1}{2}$, it follows that $\frac{V_s}{V_p} = 2$. Hence, $V_s : V_p = 2 : 1$.