Question

In an ice rink a skator is moving at 3 ms^-1 and encounters a rough patch that reduces her speed by 45% due to a friction force that is 25% of her weight. Find the length of the rough patch

• A. 1.56 m
• B. 1.46 m
• C. 1.36 m
• D. 1.26 m

Answer 1

Answer: (D)

1.26 m

Answer 2

= $\frac{v_{i}^{2} - v_{f}^{2}}{2\mu g} = \frac{3^{2}\left( 1 - (.55)^{2} \right)}{2 \times 2.5}$

= 1.8 [.7] = 1.26 m