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Question: In an experiment with 15 observations on x, the following results were available \(\sum x^{2} = 2830...

In an experiment with 15 observations on x, the following results were available x2=2830\sum x^{2} = 2830, x=170\sum x = 170. On observation that was 20 was found to be wrong and was replaced by the correct value 30. Then the corrected variance is

A

78.00

B

188.66

C

177.33

D

8.33

Answer

78.00

Explanation

Solution

x=170\sum x = 170, x2=2830\sum x^{2} = 2830

Increase in x=10\sum x = 10, then x=170+10=180\sum x^{'} = 170 + 10 = 180

Increase in x2=900400=500\sum x^{2} = 900 - 400 = 500, then

x=2830+500=3330\sum x^{'} = 2830 + 500 = 3330

Variance=1nx2(xn)2=333015(18015)2=222144=78= \frac{1}{n}\sum x^{'2} - \left( \frac{\sum x^{'}}{n} \right)^{2} = \frac{3330}{15} - \left( \frac{180}{15} \right)^{2} = 222 - 144 = 78