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Question: In an experiment tungsten cathode which has a threshold wavelength 2300 Å is irradiated by ultraviol...

In an experiment tungsten cathode which has a threshold wavelength 2300 Å is irradiated by ultraviolet light of wavelength 1800 Å. The maximum energy of emitted photo-electron will be –

A

1.2 eV

B

1.5 eV

C

1.6 eV

D

1.8 eV

Answer

1.5 eV

Explanation

Solution

Kmax = hc (1λ1λ0)\left( \frac { 1 } { \lambda } - \frac { 1 } { \lambda _ { 0 } } \right)

= 6.62×1034×3×1081.6×1019\frac { 6.62 \times 10 ^ { - 34 } \times 3 \times 10 ^ { 8 } } { 1.6 \times 10 ^ { - 19 } } (1010180010102300)\left( \frac { 10 ^ { 10 } } { 1800 } - \frac { 10 ^ { 10 } } { 2300 } \right)

= 1.5 eV