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Physics Question on Newtons Law of Cooling

In an experiment to verify Newton’s law of cooling, a graph is plotted between, the temperature difference (ΔT) of the water and surroundings and time as shown in figure. The initial temperature of water is taken as 80ºC. The value of t2t_2 as mentioned in the graph will be ______.graph is plotted between, the temperature difference ΔT of the water and surroundings and time

Answer

Temperature of surrounding == 20ºC20ºC
For 00 to 66 minutes, average temp. == 70ºC70ºC
Rate of cooling 70ºC20ºC=50ºC∝70ºC – 20ºC = 50ºC
For 66 to t2t_2 minutes, average temp. =50ºC= 50ºC
Rate of cooling 30ºC∝30ºC
t26=53⇒ t_2-6 = \frac 53 (66 minutes)
t2=16⇒ t_2= 16 minutes

So, the answer is 1616 minutes.