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Question: In an experiment on measurements of emf of a cell by a potentiometer, the balancing length for a cel...

In an experiment on measurements of emf of a cell by a potentiometer, the balancing length for a cell of emf E and internal resistance r is found to be l. Now if another cell of emf E and internal resistance 2r is connected in parallel to the first cell and balancing length determined, then the balancing length will be-

A

l

B

2 l

C

l2\frac{\mathcal{l}}{2}

D

23l\frac{2}{3}\mathcal{l}

Answer

l

Explanation

Solution

balancing length = l

Enet = E ⇒ balancing length = l