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Question

Physics Question on Resistance

In an experiment of Wheatstone bridge, a null point is obtained at the centre of the bridge wire. When a resistance of 10Ω10 \, \Omega is connected in one gap, the value of resistance in other gap is

A

10Ω10\, \Omega

B

5Ω5 \,\Omega

C

12Ω\frac{1}{2}\,\Omega

D

500Ω500\,\Omega

Answer

10Ω10\, \Omega

Explanation

Solution

According to Wheatstone bridge principle PQ=RS\frac{P}{Q}=\frac{R}{S} Let length of bridge wire is 100cm100\, cm. RS=l100l\therefore \frac{R}{S}=\frac{l}{100-l} Here R=10Ω,l=50cm R=10 \,\Omega, l=50\, cm 10S=5010050\frac{10}{S} =\frac{50}{100-50} S=10ΩS =10\, \Omega