Question
Question: In an experiment of verification of Ohm's law, following observations are obtained. Potential...
In an experiment of verification of Ohm's law, following observations are obtained.
Potential Difference V (in volt) | 0.5 | 1.0 | 1.5 | 2.0 | 2.5 |
---|---|---|---|---|---|
Current (in Ampere) | 0.2 | 0.4 | 0.6 | 0.8 | 1.0 |
From observation table the resistance in the circuit is
A. 2.5Ω
B. 2Ω
C. 5Ω
D. 3Ω
Solution
Use Ohm's law. It shows the relationship between voltage, current and resistance in an electric circuit. Ohm's law states that the current passing through a conductor between two points is directly proportional to the voltage across two points. Substitute the given values in that formula and calculate the resistance.
Complete step by step answer:
According to Ohm's Law,
V=IR
Where, V is the potential difference across the conductor
I is the current flowing through the resistor
R is the resistance
Rearranging the above equation we get,
R=IV
Substituting each value of potential difference and current in the above equation we get,
R=0.20.5
∴R=2.5Ω
R=0.41.0
∴R=2.5Ω
R=0.61.5
∴R=2.5Ω
R=0.82.0
∴R=2.5Ω
R=1.02.5
∴R=2.5Ω
Thus, the resistance in the circuit is 2.5Ω.
Hence, the correct answer is option A i.e. 2Ω.
Note:
Current-Voltage relationship is generally represented in the form of graphs. Voltage is plotted along the X-axis of the graph and current is plotted along the Y-axis of the graph. Voltage versus current graph gives a straight line and has a constant slope. If the conductor has a constant slope in current versus voltage graph then it is called a Ohmic Conductor. But if the conductor does not obey Ohm's law and the resistance is not constant then the conductor is called Non-ohmic conductor.
The graph for the given table is shown below: