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Question

Physics Question on Ray optics and optical instruments

In an experiment for determination of the focal length of a thin convex lens, the distance of the object from the lens is 10 ± 0.1 cm and the distance of its real image from the lens is 20 ± 0.2 cm. The error in the determination of focal length of the lens is 𝑛 %. The value of 𝑛 is ____ .

Answer

Object distance =10±0.1= 10 ± 0.1 cm Image distance =20±0.2= 20 ± 0.2 cm
Applying lens formula ….. (1)

120110=1f\frac {1}{20} - \frac{1}{-10} = \frac {1}{f}

f = 203cm\frac{20}{3} cm

differentiate equation 1:

1f2df=+1v2dv+1u2du\frac {1}{f^2}df = +\frac{1}{v^2}dv+\frac{1}{u^2}du

dff×100=0.2202+0.1102×203×100\frac{df}{f}\times 100 = \frac{0.2}{20^2}+\frac{0.1}{10^2}\times \frac{20}{3}\times 100

= 1

dff×100=1\frac{df}{f}\times 100 = 1%

So, the answer is 11.