Solveeit Logo
Login

Question

Physics Question on thermal properties of matter

In an experiment a sphere of aluminium of mass 0.20 kg is heated upto 150∘C150^{\circ}C. Immediately, it is put into water of volume 150 cc at 27∘C27^{\circ}C kept in a calorimeter of water equivalent to 0.025 kg. Final temperature of the system is 40∘C40^{\circ}C. The specific heat of aluminium is : (take 4.2 Joule=1 calorie)

A

378 J/kg−∘C378 \, J/kg - {^{\circ}C}

B

315 J/kg−∘C315 \, J/kg - {^{\circ}C}

C

476 J/kg−∘C476 \, J/kg - {^{\circ}C}

D

434 J/kg−∘C434 \, J/kg - {^{\circ}C}

Answer

434 J/kg−∘C434 \, J/kg - {^{\circ}C}

Explanation

Solution

Q given = Q used
⇒m1C1ΔT1=(m2+w)C2ΔT2\Rightarrow m _{1} C _{1} \Delta T _{1}=\left( m _{2}+ w \right) C _{2} \Delta T _{2}
⇒0.20×C1×(150−40)=(150×10−3)\Rightarrow 0 . 2 0 \times C _{1} \times( 1 5 0 - 4 0 )=\left( 1 5 0 \times 1 0 ^{-3}\right)
C1=434 ykg−1k−1C _{1}= 4 3 4 ~ y k g ^{-1} k ^{-1}