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Question: In an experiment, \(1.0g\) \(CaC{{O}_{3}}\) on heating evolved \(224ml\) of \(C{{O}_{2}}\) at NTP. W...

In an experiment, 1.0g1.0g CaCO3CaC{{O}_{3}} on heating evolved 224ml224ml of CO2C{{O}_{2}} at NTP. What mass of CaOCaO (calcium oxide) is formed?
A.0.560.56
B.5656
C.0.570.57
D.0.580.58

Explanation

Solution

Mole concept gives the relationship between the number of moles, weight and molar mass of the compound. Molar mass is calculated by adding up the atomic masses of the element combined to form a molecule.

Formula used:
n=WMn=\dfrac{W}{M}
Where, nn is the number of moles, WW is the weight of the compound and MM is the molar mass of the compound.
Complete step-by-step answer: In this question, it is given that the moles of CaCO3CaC{{O}_{3}} is 1g1g
Volume of CO2C{{O}_{2}} is 224ml224ml which is equal to 0.224l0.224l
The molar mass of CaCO3CaC{{O}_{3}}is 100gmol1100gmo{{l}^{-1}}
Now we will apply mole concept to calculate the moles of CaCO3CaC{{O}_{3}}
n=WMn=\dfrac{W}{M}
Where, nn is the number of moles, WW is the weight of the compound and MM is the molar mass of the compound.
Now, we will substitute the values in the above formula we get,
n=1100n=\dfrac{1}{100}
n=0.01moln=0.01mol
The moles of CaCO3CaC{{O}_{3}}is 0.01mol0.01mol
Now, we will calculate the moles of CO2C{{O}_{2}}
At STP,
n=V22.4ln=\dfrac{V}{22.4l}
Now substituting the value of volume of CO2C{{O}_{2}} in litres we get,
n=0.22422.4n=\dfrac{0.224}{22.4}
n=0.01moln=0.01mol
The moles of CO2C{{O}_{2}}is 0.01mol0.01mol
The thermal decomposition reaction of CaCO3CaC{{O}_{3}} is
CaCO3CaO+CO2CaC{{O}_{3}}\to CaO+C{{O}_{2}}
0.01mol0.01mol of CaCO3CaC{{O}_{3}}will decompose to give 0.01mol0.01mol of CaOCaO and 0.01mol0.01mol of CO2C{{O}_{2}}
The molar mass of CaOCaO is 56gmol156gmo{{l}^{-1}}
On applying mole concept we get,
n=WMn=\dfrac{W}{M}
Where, nn is the number of moles, WW is the weight of the compound and MM is the molar mass of the compound.
On substituting the values we get,
0.01=W560.01=\dfrac{W}{56}
W=0.56gW=0.56g
Therefore, the mass of CaOCaO is 0.56g0.56g

Hence, the correct option is A.

Note: Moles are defined as a scientific unit which is used to measure large quantities of atoms and molecules. It is defined as the amount of substance present in sample.
1mole=6.022×1023particles1mole=6.022\times {{10}^{23}}particles
This is also called as Avogadro’s number (NA)\left( {{N}_{A}} \right) .
-Molar mass is defined as the addition of atomic mass of atoms, combined in a molecule. Here, the molar mass of CaCO3CaC{{O}_{3}} is 100gmol1100gmo{{l}^{-1}} .
-Moles are defined as the weight if the compound per molar mass of the compound.
-Formula mass is different from molecular mass. In formula mass, there is an addition of atomic masses of ion present in an ionic compound, whereas molecular mass is the addition of atomic masses of the atoms in a molecule