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Question: In an excited state of hydrogen like atom an electron has a total energy of –3.4 eV. If the kinetic ...

In an excited state of hydrogen like atom an electron has a total energy of –3.4 eV. If the kinetic energy of the electron is E and its de Broglie wavelength l, then–

A

E = 6.8 eV ,l ~ 6.6 × 10–10m

B

E = 3.4eV, l ~ 6.6 × 10–10 m

C

E = 3.4 eV, l ~ 6.6 × 10–11 m

D

E = 6.8 eV, l ~ 6.6 × 10–11 m

Answer

E = 3.4eV, l ~ 6.6 × 10–10 m

Explanation

Solution

l = h2mE\frac{h}{\sqrt{2mE}}, l = 12.27VA˚\frac{12.27}{\sqrt{V}}Å