Question
Mathematics Question on Permutations and Combinations
In an examination paper there are two groups, each containing 4 questions. A candidate is required to attempt 5 questions but not more than 3 questions from any group. In how many ways can 5 questions be selected?
24
48
96
None of these
48
Solution
The correct option is (B): 48
The problem requires selecting 5 questions from two groups of 4 questions each, with the restriction that not more than 3 questions can be selected from any group.
Step 1: Understand the possibilities
To satisfy the condition that no more than 3 questions can be selected from any group, the possible combinations of questions from Group 1 and Group 2 are:
- 3 questions from Group 1 and 2 questions from Group 2
- 2 questions from Group 1 and 3 questions from Group 2
Step 2: Calculate each case
1. Selecting 3 questions from Group 1 and 2 questions from Group 2:
The number of ways to choose 3 questions from 4 in Group 1 is C(34), and the number of ways to choose 2 questions from 4 in Group 2 is C(24).
So, the number of ways is:
C(34) \times C(24) = 4 \times 6 = 24]
2. Selecting 2 questions from Group 1 and 3 questions from Group 2:
The number of ways to choose 2 questions from 4 in Group 1 is (24), and the number of ways to choose 3 questions from 4 in Group 2 is (34).
So, the number of ways is:
(24)×(34)=6×4=24
Step 3: Total number of ways
The total number of ways to select the questions is:
24+24=48
Final Answer:
The number of ways to select 5 questions is 48.