Solveeit Logo

Question

Mathematics Question on Permutations and Combinations

In an examination paper there are two groups, each containing 4 questions. A candidate is required to attempt 5 questions but not more than 3 questions from any group. In how many ways can 5 questions be selected?

A

24

B

48

C

96

D

None of these

Answer

48

Explanation

Solution

The correct option is (B): 48
The problem requires selecting 5 questions from two groups of 4 questions each, with the restriction that not more than 3 questions can be selected from any group.

Step 1: Understand the possibilities
To satisfy the condition that no more than 3 questions can be selected from any group, the possible combinations of questions from Group 1 and Group 2 are:

- 3 questions from Group 1 and 2 questions from Group 2
- 2 questions from Group 1 and 3 questions from Group 2

Step 2: Calculate each case
1. Selecting 3 questions from Group 1 and 2 questions from Group 2:
The number of ways to choose 3 questions from 4 in Group 1 is C(43)C\binom{4}{3}, and the number of ways to choose 2 questions from 4 in Group 2 is C(42)C\binom{4}{2}.

So, the number of ways is:
C(43)C\binom{4}{3} \times C(42)C\binom{4}{2} = 4 \times 6 = 24]

2. Selecting 2 questions from Group 1 and 3 questions from Group 2:
The number of ways to choose 2 questions from 4 in Group 1 is (42)\binom{4}{2}, and the number of ways to choose 3 questions from 4 in Group 2 is (43)\binom{4}{3}.

So, the number of ways is:
(42)×(43)=6×4=24\binom{4}{2} \times \binom{4}{3} = 6 \times 4 = 24

Step 3: Total number of ways
The total number of ways to select the questions is:
24+24=4824 + 24 = 48

Final Answer:
The number of ways to select 5 questions is 48.