Question
Question: In an ellipse, the distance between its foci is 6 and the minor axis is 8. Then its eccentricity is:...
In an ellipse, the distance between its foci is 6 and the minor axis is 8. Then its eccentricity is:
A. 53
B. 21
C. 54
D. 51
Solution
Hint : We know that the eccentricity of an ellipse can be defined as the ratio of its linear eccentricity to the length of the semi major axis. Here, linear eccentricity is the distance of the focal point to the center of the ellipse. We will use this definition along with the equation of ellipse to find the eccentricity of the given ellipse.
Complete step-by-step answer :
We know that the equation of ellipse is given by
a2x2+b2y2=1,a>b
Here, we are given that the minor axis is 8.
⇒2b=8
As per the definition of eccentricity of the ellipse,
e=ac , where, c is the linear eccentricity and a is the semi major axis,
Also as per the definition of linear eccentricity,
c=2f , Where, f is the distance between foci of an ellipse
Putting the value of c in the equation of eccentricity, we get
\dfrac{{2b}}{{2ae}} = \dfrac{8}{6} \\
\Rightarrow \dfrac{b}{{ae}} = \dfrac{4}{3} $$
Squaring both the sides,
\Rightarrow 1 - {e^2} = \dfrac{{16}}{9}{e^2} \\
\Rightarrow 1 = \dfrac{{16}}{9}{e^2} + {e^2} \\
\Rightarrow 1 = \dfrac{{16 + 9}}{9}{e^2} $$