Question

In an electrolyte $3.2 \times 10 ^ { 18 }$ bivalent positive ions drift to the right per second while $3.6 \times 10 ^ { 18 }$ monovalent negative ions drift to the left per second. Then the current is

• A. 1.6 amp to the left
• B. 1.6 amp to the right
• C. 0.45 amp to the right
• D. 0.45 amp to the left

Answer 1

Answer: (B)

1.6 amp to the right

Answer 2

Net current $i _ { \text {net } } = i _ { ( + ) } + i _ { ( - ) }$

$= \frac { n _ { ( + ) } q _ { ( + ) } } { t } + \frac { n _ { ( - ) } q _ { ( - ) } } { t }$

$= \frac { n _ { ( + ) } } { t } \times 2 e + \frac { n _ { ( - ) } } { t } \times e$

= 3.2 × 10¹⁸ × 2 × 1.6 × 10^–19 + 3.6 × 10¹⁸ × 1.6 × 10^–19 = 1.6 A (towards right)