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Question

Physics Question on Current electricity

In an electrical circuit, the voltage is measured as V = (200 ± 4) volt and the current is measured as I = (20 ± 0.2) A. The value of the resistance is:

A

(10 ± 4.2) Ω

B

(10 ± 0.3) Ω

C

(10 ± 0.1) Ω

D

(10 ± 0.8) Ω

Answer

(10 ± 0.3) Ω

Explanation

Solution

Resistance (R) = VI=20020=10Ω\frac{V}{I} = \frac{200}{20} = 10 \, \Omega

ΔRR=ΔVV+ΔII\frac{\Delta R}{R} = \frac{\Delta V}{V} + \frac{\Delta I}{I}

ΔR10=4200+0.220=0.02+0.01=0.03\frac{\Delta R}{10} = \frac{4}{200} + \frac{0.2}{20} = 0.02 + 0.01 = 0.03

ΔR=0.3Ω\Delta R = 0.3 \, \Omega

Thus, R = (10 ± 0.3) Ω