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Question

Question: In an AP : S<sub>n</sub> = n<sup>2</sup> – 2n , then fifth term is –...

In an AP : Sn = n2 – 2n , then fifth term is –

A

5

B

7

C

8

D

None

Answer

7

Explanation

Solution

Tn = (2n – 1) – 2(1) = 2n – 3 T5 = 10 – 3 = 7