Question

In an alkaline condition $KMnO_4$ reacts as follows :${2KMnO_4 + 2KOH -> 2K_2MnO_4 + H_2O + O}$ Its equivalent weight is

• A. 31.6
• B. 52.7
• C. 49
• D. 158

Answer 1

Answer: (D)

158

Answer 2

Equivalent mass of $KMnO _{4}=\frac{\text { Molecular W eight }}{ No \text { of } e ^{-} \text {gained }}$ $MnO _{4}^{-}+ e ^{-} \rightarrow MnO _{4}^{-2}$ The number of electrons gained per molecule of is $1 .$ So, the equivalent mass is 158 .