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Question: In an accelerator experiment on high energy collisions of electrons with positrons, a certain event ...

In an accelerator experiment on high energy collisions of electrons with positrons, a certain event is interpreted as annihilation of an electron-positron pair of total energy 10.2×10910.2 \times 10^{9}eV into two of equal energy. The wavelength associated with each γray\gamma - rayis:

A

3.21×1018m3.21 \times 10^{- 18}m

B

1.23×1016m1.23 \times 10^{- 16}m

C

2.44×1016m2.44 \times 10^{- 16}m

D

4.21×1014m4.21 \times 10^{- 14}m

Answer

2.44×1016m2.44 \times 10^{- 16}m

Explanation

Solution

: Here total energy of 2γrays=10.2×109eV2\gamma - rays = 10.2 \times 10^{9}eV

\thereforeEnergy of each γrays\gamma - rays

}{= 8.16 \times 10^{- 10}j}$$ As $E = h\upsilon = \frac{hc}{\lambda}$ Or $\lambda = \frac{hc}{E} = \frac{6.63 \times 10^{- 34} \times 3 \times 10^{8}}{8.16 \times 10^{- 10}} = 2.44 \times 10^{- 16}m$