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Question: In an ac dynamo, the peak value of emf is 60 volts, then the induced emf in the position, when armat...

In an ac dynamo, the peak value of emf is 60 volts, then the induced emf in the position, when armature makes an angle of 30o with the magnetic field perpendicular with the coil, will be

A

20 volts

B

30330\sqrt{3}volts

C

30 volts

D

45 volts

Answer

30 volts

Explanation

Solution

e=e0sinωte = e_{0}\sin\omega t = e0 sin θ = 60 sin30o = 30 volts