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Question: In an ac circuit, V and I are given by V = 100 sin (100 t) volts, \(I = 100 \sin \left( 100 t + \fr...

In an ac circuit, V and I are given by

V = 100 sin (100 t) volts, I=100sin(100t+π3)mAI = 100 \sin \left( 100 t + \frac { \pi } { 3 } \right) m A.

The power dissipated in circuit is

A

104 watt

B

10 watt

C

2.5 watt

D

5 watt

Answer

2.5 watt

Explanation

Solution

=1002×100×1032×cosπ3= \frac { 100 } { \sqrt { 2 } } \times \frac { 100 \times 10 ^ { - 3 } } { \sqrt { 2 } } \times \cos \frac { \pi } { 3 }

=104×1032×12=104=2.5watt= \frac { 10 ^ { 4 } \times 10 ^ { - 3 } } { 2 } \times \frac { 1 } { 2 } = \frac { 10 } { 4 } = 2.5 \mathrm { watt }