Question
Physics Question on Electromagnetic induction
In an ac circuit , an alternating voltage e=2002sin100t volts is connected to a capacitor of capacitance 1μF. The rms value of the current in the circuit is :
A
10 mA
B
100 mA
C
200 mA
D
20 mA
Answer
20 mA
Explanation
Solution
given e=2002sin100t
ω=100secrad
Erms=22002
C=1×10−6
Z=Xc=ωC1=100×10−61=104Ω
I=ZErms=10422002=2×10−2A=20mA