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Question

Physics Question on Electromagnetic induction

In an ac circuit , an alternating voltage e=2002sin100te = 200 \sqrt2 \,sin \,100\, t volts is connected to a capacitor of capacitance 1μF1 \,\mu \,F. The rms value of the current in the circuit is :

A

10 mA

B

100 mA

C

200 mA

D

20 mA

Answer

20 mA

Explanation

Solution

given e=2002sin100te =200 \sqrt{2} \sin 100 t
ω=100radsec\omega=100 \frac{ rad }{ sec }
Erms=20022E _{ rms }=\frac{200 \sqrt{2}}{\sqrt{2}}
C=1×106C =1 \times 10^{-6}
Z=Xc=1ωC=1100×106=104ΩZ = X _{ c }=\frac{1}{\omega C }=\frac{1}{100 \times 10^{-6}}=10^{4} \Omega
I=ErmsZ=20022104=2×102A=20mAI =\frac{ E _{ rms }}{ Z }=\frac{\frac{200 \sqrt{2}}{\sqrt{2}}}{10^{4}}=2 \times 10^{-2} A =20 mA