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Question

Mathematics Question on Arithmetic Progression

In an A.P., if a=8a = 8 and a10=19a_{10} = -19, then value of dd is:

A

33

B

119-\frac{11}{9}

C

2710-\frac{27}{10}

D

3-3

Answer

3-3

Explanation

Solution

In an arithmetic progression (A.P.), the nn-th term is given by the formula:

an=a+(n1)da_n = a + (n - 1)d

Where:

  • ana_n is the nn-th term,
  • aa is the first term,
  • dd is the common difference.

We are given:

  • a=8a = 8 (the first term),
  • a10=19a_{10} = -19 (the 10th term),
  • We need to find dd (the common difference).

Substitute the known values into the formula for the 10th term:

a10=a+(101)d    19=8+9da_{10} = a + (10 - 1)d \implies -19 = 8 + 9d

Now, solve for dd:

198=9d    27=9d    d=3-19 - 8 = 9d \implies -27 = 9d \implies d = -3

Thus, the correct answer is:

d) 3d)\ -3