Question

In an A.C. circuit, V and I are given by V=150 sin(150 t) volt and I=150 $Sin(150 t+\frac {\pi}{3})$A. The power dissipated in the circuit is

• A. 106 W
• B. 150 W
• C. 5625 W
• D. zero

Answer 1

Answer: (C)

5625 W

Answer 2

Given $V =150 \sin (150 t)$ volt
$I=150 \sin (150 t+\frac{\pi}{ 3})$ A
$\therefore I_{0}=150$ A
and $V_{0}=150$ V
$P =\frac{1}{2} V_{0} I_{0} \cos \phi$
$P =0.5 \times 150 \times 150 \times \cos 60^{\circ}$
$P =5625\, W$
The correct option is(C): 5625 W.