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Question

Chemistry Question on Redox reactions

In acidic medium, MnO42−MnO_4 ^{2-}

A

disproportionates to MnO2MnO_2 and MnO4−MnO_4 ^-

B

is oxidised to MnO4−MnO_4^ -

C

is reduced to MnO2MnO_2

D

is reduced to Mn2+Mn^{2+}.

Answer

disproportionates to MnO2MnO_2 and MnO4−MnO_4 ^-

Explanation

Solution

MnO42−MnO_4^{ 2-} disproportionates in acidic medium as follows: 3MnO42−+4H+−>2MnO4−+MnO2+2H2O {3MnO4^{2-} + 4H^{+} -> 2MnO4^{-} + MnO2 + 2H2O}