Question

In acid medium nitrobenzene is reduced to aniline as shown in the reaction

$C_{6}H_{5} - NO_{2} + 6\lbrack H\rbrack \rightarrow C_{6}H_{5} - NH_{2} + 2H_{2}O$

The reducing agent used in this reaction is …….

• A. $LiAlH_{4}$
• B. $Sn ⥂ / ⥂ HCl$
• C. Na/alcohol
• D. $H_{2} ⥂ ⥂ / ⥂ Ni$

Answer 1

Answer: (B)

$Sn ⥂ / ⥂ HCl$

Answer 2

$C_{6}H_{5}NO_{2} + 6H\overset{\quad Sn + HCl\quad}{\rightarrow}C_{6}H_{5} - NH_{2} + 2H_{2}O$