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Question: In ∆ABC, a cos (B – C) + b cos (C – A) + c cos (A – B) (where a, b, c are sides of ∆) equals...

In ∆ABC, a cos (B – C) + b cos (C – A) + c cos (A – B) (where a, b, c are sides of ∆) equals

A
B

abc4R2\frac { \mathrm { abc } } { 4 \mathrm { R } ^ { 2 } }

C

4abcR2\frac { 4 a b c } { R ^ { 2 } }

D

None

Answer
Explanation

Solution

a = 2R sin A

b = 2R sin B

& c = 2R sin C