Question
Question: In ∆ABC, a cos (B – C) + b cos (C – A) + c cos (A – B) (where a, b, c are sides of ∆) equals...
In ∆ABC, a cos (B – C) + b cos (C – A) + c cos (A – B) (where a, b, c are sides of ∆) equals
A

B
4R2abc
C
R24abc
D
None
Answer

Explanation
Solution
a = 2R sin A
b = 2R sin B
& c = 2R sin C