Solveeit Logo

Question

Question: In \(A^{+}B^{-}\)ionic compound, radii of \(A^{+}\)and \(B^{-}\)ions are \(180pm\) and \(187pm\) res...

In A+BA^{+}B^{-}ionic compound, radii of A+A^{+}and BB^{-}ions are 180pm180pm and 187pm187pm respectively. The crystal structure of this compound will be.

A

NaClNaCl type

B

CsClCsCl type

C

ZnSZnS type

D

Similar to diamond

Answer

CsClCsCl type

Explanation

Solution

r+/r=180187=0.962r_{+}/r_{-} = \frac{180}{187} = 0.962 which lies in the range of 0.7321.0000.732 - 1.000, hence co-ordination number = 8 i.e. the structure is CsClCsCl type.