Question

In a Young's double slit experiment, let S₁& S₂ be the two slits and C be the centre of the screen if ĐS₁CS₂ = q and l is the wavelength, the fringe width will be –

• A. $\frac{\lambda}{\theta}$
• B. lq
• C. $\frac{2\lambda}{\theta}$
• D. $\frac{\lambda}{2\theta}$

Answer 1

Answer: (A)

$\frac{\lambda}{\theta}$

Answer 2

Dq = d

b = $\frac{\lambda D}{d}$= $\frac{\lambda D}{D\theta}$ = $\frac{\lambda}{\theta}$