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Question

Physics Question on Wave optics

In a Young?? double slit experiment with light of wavelength λ\lambda, fringe pattern on the screen has fringe width β\beta. When two thin transparent glass (refractive index μ\mu) plates of thickness t1t_1 and t2t_2 (t1>t2)(t_1 > t_2) are placed in the path of the two beams respectively, the fringe pattern will shift by a distance

A

β(μ1)λ(t1t2)\frac{\beta\left(\mu-1\right)}{\lambda} \left(\frac{t_{1}}{t_{2}}\right)

B

μβλt1t2\frac{\mu\beta}{\lambda} \frac{t_{1}}{t_{2}}

C

β(μ1)λ(t1t2)\frac{\beta\left(\mu-1\right)}{\lambda} \left(t_{1}-t_{2}\right)

D

(μ1)λβ(t1+t2)\left(\mu-1 \right)\frac{\lambda}{\beta} \left(t_{1}+t_{2}\right)

Answer

β(μ1)λ(t1t2)\frac{\beta\left(\mu-1\right)}{\lambda} \left(t_{1}-t_{2}\right)

Explanation

Solution

Shift =β(μ1)λt1β(μ1)λt2=\frac{\beta\left(\mu-1\right)}{\lambda}t_{1}- \frac{\beta \left(\mu -1\right)}{\lambda }t_{2} =β(μ1)λ(t1t2)=\frac{\beta \left(\mu -1\right)}{\lambda }\left(t_{1}-t_{2}\right)