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Question

Physics Question on Wave optics

In a Young' double slit experiment. if there is no initial phase difference between the light from the two slits, a point on the screen corresponding to the fifth minimum has path difference.

A

5λ25\frac{\lambda}{2}

B

10λ210\frac{\lambda}{2}

C

9λ29\frac{\lambda}{2}

D

11λ211\frac{\lambda}{2}

Answer

9λ29\frac{\lambda}{2}

Explanation

Solution

Path difference for nthn^{th} minima =(2n1)λ2=(2n - 1) \frac{\lambda}{2}
For fifth minima (n=5)=9λ2(n = 5) = \frac{9\lambda}{2}
Therefore, the correct option is (C) : 9λ29\frac{\lambda}{2}