Question

In a volumetric experiment, it was found that a solution of $KMnO _{4}$ is reduced to $MnSO _{4}$. If the normality of the solution is $1.0\, N$, then the molarity of the solution will be

• A. 0.5 M
• B. 0.2 M
• C. 1.0 M
• D. 0.4 M

Answer 1

Answer: (B)

0.2 M

Answer 2

$2K\overset{+7}{M}\,nO_{4}+3H_{2}SO_{4}\rightarrow K_{2}SO_{4}+2\overset{+2}{M}nSO_{4} + 3H_{2}O+5O$
$\because$ Normality of the solution $=1.0\,N$
$\therefore$ Molarity of the solution $=\frac{\text{Normality}}{\text{Charge on}ON}$
$=\frac{1.0}{5}=0.2\,M$