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Question

Physics Question on Units, Dimensions and Measurements

In a Vernier caliper, N+1N+1 divisions of vernier scale coincide with NN divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is:

A

110N\frac{1}{10N}

B

1100(N+1)\frac{1}{100(N+1)}

C

100N100N

D

10N+110N+1

Answer

1100(N+1)\frac{1}{100(N+1)}

Explanation

Solution

Vernier constant is the least count and is calculated as:
V.C. = 1 MSD - 1 VSD.
Substituting:
V.C. = 0.10.1N+1=0.1N+1mm=1100(N+1)cm0.1 - \frac{0.1}{N + 1} = \frac{0.1}{N + 1} \, mm = \frac{1}{100(N + 1)} \, cm.