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Question: In a uniform electric field, a point charge of mass $m$ and charge $q$ is released from rest. If the...

In a uniform electric field, a point charge of mass mm and charge qq is released from rest. If there are no other forces acting on the particle, then which of the following graphs, correctly show the dependence of the particles speed vv on the distance xx travelled by it?

A

Graph 1

B

Graph 2

C

Graph 3

D

Graph 4

Answer

Graph 4

Explanation

Solution

Using kinematics under constant acceleration:

  • The electric force F=qEF=qE is constant, so the acceleration a=F/m=qE/ma = F/m = qE/m is constant.
  • From kinematics, for motion from rest with constant acceleration,
v2=2axv=2axx.v^2 = 2ax \quad\Longrightarrow\quad v = \sqrt{2ax}\propto \sqrt{x}.
  • The function vxv\sim\sqrt{x} is concave upward, starting with infinite slope at x=0x=0 and gradually flattening less steeply as xx increases.
  • Among the given sketches, Graph 4 matches the shape of vxv\propto\sqrt{x}. It shows vv rising from zero with a continuously increasing slope that diminishes in curvature, exactly the x\sqrt{x} profile.