Question

In a uniform electric field a charge of $3\, C$ experiences a force of $3000\, N$. The potential difference between two points $1\, cm$ apart along the electric line of force will be

• A. 10 V
• B. 30 V
• C. 300 V
• D. 100 V

Answer 1

Answer: (A)

10 V

Answer 2

As $E=\frac{F}{q}=\frac{3000 N}{3 C}=1000 N C^{-1}.$ $dr = 1 cm = 10^{-2} m$ $dV = E\left(dr\right) = 1000 \times 10^{-2} = 10 V$