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Question: In a triode amplifier, \(\mu = 25,r_{p} = 40\) kilo ohm and load resistance \(R_{L} = 10\) kilo ohm....

In a triode amplifier, μ=25,rp=40\mu = 25,r_{p} = 40 kilo ohm and load resistance RL=10R_{L} = 10 kilo ohm. If the input signal voltage is 0.5 volt, then output signal voltage will be.

A

1.25 volt

B

5 volt

C

2.5 volt

D

10 volt

Answer

2.5 volt

Explanation

Solution

Voltage gain

=VoutVin=μ1+rpRLVout0.5=251+40×10310×103= \frac{V_{\text{out}}}{V_{\text{in}}} = \frac{\mu}{1 + \frac{r_{p}}{R_{L}}} \Rightarrow \frac{V_{\text{out}}}{0.5} = \frac{25}{1 + \frac{40 \times 10^{3}}{10 \times 10^{3}}}

Vout=2.5V\Rightarrow V_{\text{out}} = 2.5V.