Question
Question: In a triangle ABC , sinA , sinB , sinC are in AP then The altitudes are in AP The altitudes are ...
In a triangle ABC , sinA , sinB , sinC are in AP then
The altitudes are in AP
The altitudes are in HP
The angles are in AP
The angles are in HP
Solution
Hint - In such questions representing all the three sides a , b , c in terms of a constant like area of the triangle would be used to find the relation between all the sides . Using what is given in the question with the sine formula would give you the desired result .
Complete step-by-step answer:
Let us consider the triangle ABC with sides a, b, c and altitude h1,h2,h3 upon the base BC , AC , AB respectively .
Let the area of the triangle ABC be R
R = 21 (h1×a) = 21 (h2×b) = 21 (h3×c)
( area of the triangle = 21 base × height )
⇒ a=h12R;b=h22R;c=h32R
Now using the sine formula
sinAa=sinBb=sinCc = k (constant)
⇒ sinA = ka ; sinB = kb ; sinC = kc
$$$$
Now according to the question sinA , sinB , sinC are in AP
⇒ ka,kb,kc are in AP
Now , putting values of a , b , c from above ,
h11k2R;h21k2R;h31k2R are in AP
⇒ h11;h21;h31 are in AP ( cancelling out the constants )
Therefore ,
h1,h2,h3 are in HP
Altitudes are in HP .
Note -
In these questions it is suitable to find an indirect method rather than to directly solve what's given . Remember that each fraction in the Sine Rule formula should contain a side and its opposite angle. Note that you should try and keep full accuracy until the end of your calculation to avoid errors .
⇒ h11;h21;h31 are in AP ( cancelling out the constants )
Therefore ,
h1,h2,h3 are in HP
Altitudes are in HP .