Solveeit Logo
Login

Question

Question: In a triangle ABC, \(\sin A = \frac { 3 } { 4 }\) how many such triangles are possible....

In a triangle ABC, sin⁡A=34\sin A = \frac { 3 } { 4 } how many such triangles are possible.

A

1

B

0

C

2

D

Infinite

Answer

0

Explanation

Solution

sin⁡Aa=sin⁡Bb⇒34×5=sin⁡B7⇒sin⁡B=2120\frac { \sin A } { a } = \frac { \sin B } { b } \Rightarrow \frac { 3 } { 4 \times 5 } = \frac { \sin B } { 7 } \Rightarrow \sin B = \frac { 21 } { 20 },

which is not possible.