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Question

Mathematics Question on Properties of Inverse Trigonometric Functions

In a triangle ABC if cosA+cosB+cosC=32\cos \, A + \cos \, B + \cos \, C = \frac{3}{2} , then the triangle is

A

Right angled

B

Right angled isoceles

C

Equilateral

D

None of these

Answer

Equilateral

Explanation

Solution

We have, in ΔABC\Delta ABC cosA+cosB+cosC=32\cos\,A +\cos\,B + \cos\,C= \frac{3}{2} We know in ΔABC\Delta ABC, cosA+cosB+cosC32cos\, A + \cos\, B +\cos\,C \le \frac{3}{2} Since, cosA+cosB+cosC=32\cos\, A + \cos\, B +\cos\,C=\frac{3}{2} A=B=C=60\therefore A= B = C= 60^{\circ} Hence, ΔABC\Delta ABC is an equilateral triangle.