Question

In a triangle ABC if BC =1 and AC = 2. Then the maximum

possible value of angle A is-

• A. π/6
• B. π/4
• C. π/3
• D. π/2

Answer 1

Answer: (A)

π/6

Answer 2

$\frac{1}{\sin A}$=$\frac{2}{\sin B}$

2sin A = sin B

maximum of sin A = $\frac{1}{2}$

Hence A = π/6